4x*(20/x^2)

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Solution for 4x*(20/x^2) equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

4*(20/(x^2))*x = 0

80*x^-1 = 0 // : 80

x^-1 = 0

x należy do O

x belongs to the empty set

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